2x^2+(5(1)^2)=4

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Solution for 2x^2+(5(1)^2)=4 equation: 



2x^2+(5(1)^2)=4

We move all terms to the left:

2x^2+(5(1)^2)-(4)=0

determiningTheFunctionDomain
2x^2-4+51^2=0

We add all the numbers together, and all the variables

2x^2+2597=0

a = 2; b = 0; c = +2597;
Δ = b2-4ac
Δ = 02-4·2·2597
Δ = -20776
Delta is less than zero, so there is no solution for the equation

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